document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169559>Question 1169559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two number is 31.2/3 of one of the number is equal to 5/8 of other. find the two number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794336 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=31<BR>\n" );
document.write( "(2/3)x=(5/8)y<BR>\n" );
document.write( "multiply both sides by 24<BR>\n" );
document.write( "16x=15y<BR>\n" );
document.write( "x=(15/16)y<BR>\n" );
document.write( "so (15/16)y+(16/16)y=31<BR>\n" );
document.write( "(31/16)y=31<BR>\n" );
document.write( "31y=496<BR>\n" );
document.write( "y=16<BR>\n" );
document.write( "x=15 those are the numbers<BR>\n" );
document.write( "(2/3)x=10 (5/8)y=10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );