document.write( "Question 1169513: Consider a proper fraction such that the numerato is 2 less than the denominator. If the numerator and denominator are each increased by 1, then the ration of the numerator and denominator of the new fraction is 4:5. Determine the original fraction. \n" ); document.write( "
Algebra.Com's Answer #794271 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the original fraction is (x-2) / x
\n" ); document.write( "increase the numerator and denominator by 1 and you get (x-1) / (x+1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you get (x-1) / (x+1) = 4/5
\n" ); document.write( "cross multiply to get 5*(x-1) = 4*(x+1)
\n" ); document.write( "simplify to get 5x-5 = 4x+4
\n" ); document.write( "subtract 4x from both sides of the equation and add 5 to both sides of the equation to get 5x-4x = 4+5
\n" ); document.write( "simplify to get x = 9\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that's your answer.
\n" ); document.write( "the original fraction is 7/9.
\n" ); document.write( "add 1 to the numerator and denominator to get 8/10.
\n" ); document.write( "that simplifies to 4/5.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your solution is that the original fraction is 7/9.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );