document.write( "Question 1169507: a firm will need 300000 at the end of 3 years to repay a loan. the firm decided that it would deposit 20000 at the start of each quarter during these 3 years into the account. the account yield 12% per annum compounded quarterly during the first year. what rate of interest should it earn during the remaining 2 years to accumulate enough amount into this account to pay the loan at the end of 3 years.(Answer:13.8%) \n" ); document.write( "
Algebra.Com's Answer #794261 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "Consider the first year for now only. One year is 4 quarters. \n" ); document.write( "The 12% annual interest rate converts to the quarterly rate of (12%)/4 = 3% \n" ); document.write( "We'll let i = 0.03 to reflect this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Compute the future value (FV) of an annuity due with \n" ); document.write( "
\n" ); document.write( "We get the following \n" ); document.write( "FV = (1+i)*P*( (1+i)^n - 1)/i \n" ); document.write( "FV = (1+0.03)*20000*( (1+0.03)^4 - 1)/0.03 \n" ); document.write( "FV = 86182.7162 \n" ); document.write( "FV = 86182.72\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After four quarters pass by, we have 86182.72 in the account.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be the quarterly interest rate for the next 8 quarters (2 years). \n" ); document.write( "We'll deposit P = 86182.72 dollars at this rate and time. \n" ); document.write( "At the end of 8 quarters, we'll be left with 86182.72*(1+x)^8 dollars \n" ); document.write( "Note I'm using the compound interest formula here.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let S = 86182.72*(1+x)^8 \n" ); document.write( "We'll come back to this later.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Again keeping x the same, whatever it is, we'll compute the FV of an annuity due like we did earlier. However, this time we don't know the interest rate and the value of n is doubled (n = 8 instead of n = 4). \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have \n" ); document.write( "FV = (1+i)*P*( (1+i)^n - 1)/i \n" ); document.write( "FV = (1+x)*20000*( (1+x)^8 - 1)/x \n" ); document.write( "Let's call this R \n" ); document.write( "R = (1+x)*20000*( (1+x)^8 - 1)/x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the expressions of S and R \n" ); document.write( "S+R = 86182.72*(1+x)^8+(1+x)*20000*( (1+x)^8 - 1)/x \n" ); document.write( "call this sum T. We'll make it a function of x \n" ); document.write( "T(x) = 86182.72*(1+x)^8+(1+x)*20000*( (1+x)^8 - 1)/x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The goal is to solve T(x) = 300000 which is the same as finding the roots of T(x)-300000 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The variable x is buried under an exponent of 8, which suggests that solving this by hand is going to be daunting. Luckily we can use technology. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can use any technology you like. For me, I prefer GeoGebra since it's a very handy program in many ways. You should find the root on the interval 0 < x < 1 is approximately \n" ); document.write( "x = 0.0345028581\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This represents the decimal form of the quarterly interest rate. \n" ); document.write( "So the quarterly rate is about 3.45%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiplying this by 4 leads to the annual rate needed \n" ); document.write( "4*x = 4*0.0345 = 0.138 = 13.8%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 13.8% \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |