document.write( "Question 1169459: cos(2tan^-1(2/1)) \n" ); document.write( "
Algebra.Com's Answer #794239 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Use the following identity :\r
\n" ); document.write( "\n" ); document.write( "\"cos%282x%29=+%28-1%2B2+cos+%5E2%28x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "since \"x=tan%5E-1%282%2F1%29=tan%5E-1%282%29\", we have\r
\n" ); document.write( "\n" ); document.write( "\"cos%282tan%5E-1%282%29%29=+%28-1%2B2cos+%5E2%28tan%5E-1%282%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Use the following identity: \"cos%28tan%5E-1%28x%29%29=%28sqrt%281%2Bx%5E2%29%2F%281%2Bx%5E2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29=+%28-1%2B2%28sqrt%281%2Bx%5E2%29%2F%281%2Bx%5E2%29%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29=+%28-1%2B2%28sqrt%281%2B2%5E2%29%2F%281%2B2%5E2%29%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29=+-1%2B2%28%281%2B4%29%2F%281%2B4%29%5E2%29\"
\n" ); document.write( "
\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29=+-1%2B2%285%2F25%29\"
\n" ); document.write( "
\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29=+-1%2B2%2F5+\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29=+-3%2F5+\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%282tan%5E-1%282%2F1%29%29=+-0.6+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );