document.write( "Question 1169436: The length of a house - and - lot for sale is 6 m more than its width. The floor area is surrounded by a 3 - meter walkway. The total area of the walkway is 288 m^2. What are the dimensions of the lot? \r
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Algebra.Com's Answer #794226 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The length of a house - and - lot for sale is 6 m more than its width. \n" ); document.write( " Assuming the length of the house is 6 meters longer than the width \n" ); document.write( " L = w + 6 \n" ); document.write( ": \n" ); document.write( " The floor area is surrounded by a 3 - meter walkway. \n" ); document.write( "Over all dimensions \n" ); document.write( "(L+6) by (w+6) \n" ); document.write( " : \n" ); document.write( " The total area of the walkway is 288 m^2. \n" ); document.write( "Overall area - house area = walkway area \n" ); document.write( "(L+6)(w+6) - Lw = 288 \n" ); document.write( "Replace L with (w+6) \n" ); document.write( "(w+12)*(w+6) - w(w+6) = 288 \n" ); document.write( "FOIL \n" ); document.write( "w^2 + 6w + 12w + 72 - w^2 - 6w = 288 \n" ); document.write( "combine like terms \n" ); document.write( "w^2 - w^2 + 18w - 6w = 288 - 72 \n" ); document.write( "12w = 216 \n" ); document.write( "w = 216/12 \n" ); document.write( "w = 18 m is the width of the house \n" ); document.write( "then \n" ); document.write( "18+6 = 24 m is the length of the house \n" ); document.write( "therefore \n" ); document.write( "24+6 = 30 m is the lot length \n" ); document.write( "and \n" ); document.write( "18+6 = 24 m is the lot width \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check \n" ); document.write( "lot - house = walkway \n" ); document.write( "(30*24) - (24*18) = \n" ); document.write( "720 - 432 = 288 sq meters\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |