document.write( "Question 1169424: Please Help\r
\n" ); document.write( "\n" ); document.write( "Find a 95% confidence interval for the true population proportion.\r
\n" ); document.write( "\n" ); document.write( "In a survey of 415 adults, 59% said that they favored the proposed environmental laws.
\n" ); document.write( "Select one:\r
\n" ); document.write( "\n" ); document.write( "A.
\n" ); document.write( "59% to 63.9%\r
\n" ); document.write( "\n" ); document.write( "B.
\n" ); document.write( "54.1% to 63.9%\r
\n" ); document.write( "\n" ); document.write( "C.
\n" ); document.write( "58.8% to 59.2%\r
\n" ); document.write( "\n" ); document.write( "D.
\n" ); document.write( "56.5% to 61.5%THANK YOU!!
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Algebra.Com's Answer #794210 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
half-interval for a 95%CI of a proportion is z(0.975)*sqrt(p(1-p)/n)
\n" ); document.write( "=1.96*sqrt(0.59*0.41/415)
\n" ); document.write( "=0.0473
\n" ); document.write( "the interval is (54.27, 63.73)
\n" ); document.write( "B is the best answer
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