document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108883>Question 108883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cows cost $10, pigs cost $3 and chickens cost $0.50. A man buys 100 animals for $100. How many of each animal does he have? he must have at least one of each animal. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79420 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C = number of cows<BR>\n" );
document.write( "P = number of pigs<BR>\n" );
document.write( "Ch = number of chickens<BR>\n" );
document.write( "C + P + Ch = 100<BR>\n" );
document.write( "10C + 3P + .5Ch = 100<BR>\n" );
document.write( "Ther are 3 unknowns and only 2 equations, so there is no direct solution<BR>\n" );
document.write( "multiply both sides by 2<BR>\n" );
document.write( "20C + 6P + Ch = 200<BR>\n" );
document.write( "subtract the 1st equation from this one<BR>\n" );
document.write( "20C + 6P + Ch = 200<BR>\n" );
document.write( "C + P + Ch = 100<BR>\n" );
document.write( "19C + 5P = 100<BR>\n" );
document.write( "All you need to apply is some number sense. The 2nd term, 5P<BR>\n" );
document.write( "will either end in 5 if P is odd, or 0 if P is even.<BR>\n" );
document.write( "So if P is odd, 19C has to end in 5 for the sum to end in 0.<BR>\n" );
document.write( "If P is even, 19C has to end in 0.<BR>\n" );
document.write( "Here's some combinations:<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "P = 5<BR>\n" );
document.write( "5P = 25<BR>\n" );
document.write( "C = 5<BR>\n" );
document.write( "19C =95<BR>\n" );
document.write( "19C + 5P = 100<BR>\n" );
document.write( "95 + 25 = 120 -too much<BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "P = 3<BR>\n" );
document.write( "5P = 15<BR>\n" );
document.write( "C = 5<BR>\n" );
document.write( "19C = 95<BR>\n" );
document.write( "19C + 5P = 100<BR>\n" );
document.write( "95 + 15 = 110 -still too much<BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "P = 2<BR>\n" );
document.write( "5P = 10<BR>\n" );
document.write( "C = 10 (note that 10 is the smallest # of cows that makes 19C end in 0)<BR>\n" );
document.write( "19C = 190<BR>\n" );
document.write( "19C + 5P = 100<BR>\n" );
document.write( "190 + 10 = 200 -way too much<BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "P = 1<BR>\n" );
document.write( "5P = 5<BR>\n" );
document.write( "C = 5<BR>\n" );
document.write( "19C = 95<BR>\n" );
document.write( "19C + 5P = 100<BR>\n" );
document.write( "95 + 5 = 100 this is the answer<BR>\n" );
document.write( "-----------------------------<BR>\n" );
document.write( "Now find Ch and check both equations<BR>\n" );
document.write( "C + P + Ch = 100<BR>\n" );
document.write( "5 + 1 + Ch = 100<BR>\n" );
document.write( "Ch = 94<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "10C + 3P + .5Ch = 100<BR>\n" );
document.write( "50 + 3 + 47 = 100<BR>\n" );
document.write( "100 = 100<BR>\n" );
document.write( "So, there are 1 Pig, 5 Cows, and 94 Chickens   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );