document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169443>Question 1169443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The temperature in degrees Kelvin is 273 degrees more than the temperature in degrees Celsius. Use the formula C=59(F−32)  to write a formula for the temperature in degrees Fahrenheit F in terms of the temperature in degrees Kelvin K.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #794188 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=794188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> K = C + 273<BR>\n" );
document.write( "C = (5/9)(F-32)<BR>\n" );
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document.write( "so by substituting the RHS of the 2nd equation for C in the first:<BR>\n" );
document.write( "K = (5/9)(F-32) + 273<BR>\n" );
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document.write( "K = (5F+2297)/9\r<BR>\n" );
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document.write( "Solving for F in terms of K:<BR>\n" );
document.write( "F = (9K-2297)/5\r<BR>\n" );
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document.write( "Temperatures in Kelvin are just stated as such (i.e. \"273 Kelvin\" is the same as \"100 degrees Celsius.\"  Kelvin is an absolute temperature scale).  \r<BR>\n" );
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