document.write( "Question 1169392: Kate has a t-shirt business that has earned a total of $15 000 this year. She invests part of the
\n" ); document.write( "money at 4% per year and the rest at 5% per year. After one year she earned $690 in interest.
\n" ); document.write( "How much did she invest at each rate?
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Algebra.Com's Answer #794133 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "A quick and easy non-algebraic method for solving this kind of problem....

\n" ); document.write( "(1) All $15,000 invested at 4% would yield $600 interest; all at 5% would yield $750 interest.
\n" ); document.write( "(2) The actual interest, $690, is 90/150 = 3/5 of the way from $600 to $750. (Picture the 3 numbers on a number line if it helps....)
\n" ); document.write( "(3) Therefore, 3/5 of the total was invested at the higher rate.

\n" ); document.write( "ANSWER: 3/5 of the $15,000, or $9000, at 5%; the other $6000 at 4%.

\n" ); document.write( "CHECK: .05(9000)+.04(6000) = 450+240=690

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