document.write( "Question 1169392: Kate has a t-shirt business that has earned a total of $15 000 this year. She invests part of the
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document.write( "money at 4% per year and the rest at 5% per year. After one year she earned $690 in interest.
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document.write( "How much did she invest at each rate?
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Algebra.Com's Answer #794133 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A quick and easy non-algebraic method for solving this kind of problem.... \n" ); document.write( "(1) All $15,000 invested at 4% would yield $600 interest; all at 5% would yield $750 interest. \n" ); document.write( "(2) The actual interest, $690, is 90/150 = 3/5 of the way from $600 to $750. (Picture the 3 numbers on a number line if it helps....) \n" ); document.write( "(3) Therefore, 3/5 of the total was invested at the higher rate. \n" ); document.write( "ANSWER: 3/5 of the $15,000, or $9000, at 5%; the other $6000 at 4%. \n" ); document.write( "CHECK: .05(9000)+.04(6000) = 450+240=690 \n" ); document.write( " \n" ); document.write( " |