document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108888>Question 108888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ariana took 2 hour longer to drive 360 miles on the first day of her trip then she took to drive 250 miles on the second day.  If her speed was the same on both days, what was the driving time each day?\r<BR>\n" );
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document.write( "360-250/2=110/2=55\r<BR>\n" );
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document.write( "is that right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79409 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=st d=distance t=time s=speed<BR>\n" );
document.write( "360=s(t+2)<BR>\n" );
document.write( "s=360/(t+2)<BR>\n" );
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document.write( "250=st<BR>\n" );
document.write( "s=250/t<BR>\n" );
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document.write( "360/(t+2)=250/t<BR>\n" );
document.write( "360t(t+2)/(t+2)=250t(t+2)/t<BR>\n" );
document.write( "360t=250(t+2) no more fractions.<BR>\n" );
document.write( "360t=250t+500<BR>\n" );
document.write( "360t-250t=250t-250t+500<BR>\n" );
document.write( "110t=500<BR>\n" );
document.write( "110t/110=500/110<BR>\n" );
document.write( "t=50/11 hrs<BR>\n" );
document.write( "250/(50/11)<BR>\n" );
document.write( "=250*11/50<BR>\n" );
document.write( "=55 mph<BR>\n" );
document.write( "Always check:<BR>\n" );
document.write( "55*50/11=250 true<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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