document.write( "Question 1169385: Two dogs, each traveling 10 ft/sec, run toward each other from 500 feet apart. As they run, a flea flies from the nose of one dog to the nose of the other at 25 ft/sec. The flea flies between the dogs in this manner until it is crushed when the dogs collide. How far did the flea fly? \n" ); document.write( "
Algebra.Com's Answer #794064 by ikleyn(52782)\"\" \"About 
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document.write( "The dogs will run toward each other for  \"500%2F%2810%2B10%29\" = \"500%2F20\" = \"50%2F2\" = 25 seconds.\r\n" );
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document.write( "During this time, the traveling distance for a flea is its rate times 25, i.e. 25*25 = 625 ft.   ANSWER.\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is very old and very well known entertainment Travel & Distance problem.\r
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