document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169318>Question 1169318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square and a rectangle have the same area. The length of the rectangle is 9 inches more than twice the length of the side of the square. The width of the rectangle is 6 inches less than the side of the square. Select the expression that represents the area of the square and another expression that represents the area of the rectangle?\r<BR>\n" );
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document.write( "(x-6)(2x+9)\r<BR>\n" );
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document.write( "(x)(x)\r<BR>\n" );
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document.write( "x(2x+9)\r<BR>\n" );
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document.write( "x(x-6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793998 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is length of side of a square and x*x or x^2 is the area.<BR>\n" );
document.write( "width of rectangle ix (x-6) and length is (2x+9), so the area is (x-6)(2x+9)\r<BR>\n" );
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document.write( "Can check this<BR>\n" );
document.write( "area of rectangle is 2x^2-3x-54=x^2 area of square<BR>\n" );
document.write( "x^2-3x-54=0<BR>\n" );
document.write( "(x-9)(x+6)=9<BR>\n" );
document.write( "x=9 in<BR>\n" );
document.write( "so area of square is 81 in^2<BR>\n" );
document.write( "sides of rectangle are 3 in and 27 in and its area is 81 in^2. </SPAN>\n" );
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