document.write( "Question 1169284: Determined the vertex,focus,directrix,and axis’s of semmetry of the parabola with given equation .sketch the graph and include these points and lines\r
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\n" ); document.write( "\n" ); document.write( "(y+5/2)^2=-5(x-9/2) \n" ); document.write( "

Algebra.Com's Answer #793980 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"%28y%2B5%2F2%29%5E2=-5%28x-9%2F2%29\"$ .......compare to $\"4p%28x-h%29=%28y-k%29%5E2\"$ , you see that $\"h=9%2F2+\"$ and $\"+k=-5%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( "the vertex is at ( $\"9%2F2\"$ , $\"+-5%2F2\"$ )\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( " $\"4p=-5\"$
\n" ); document.write( " $\"p=-5%2F4\"$ \r
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\n" ); document.write( "\n" ); document.write( "The focus of parabolas in this form have a focus located at
\n" ); document.write( "( $\"h+%2B+p\"$ , $\"k\"$ ) =>
\n" ); document.write( "( $\"+9%2F2+-5%2F4\"$ , $\"-5%2F2\"$ ) =( $\"18%2F4+-5%2F4\"$ , $\"-5%2F2\"$ ) =( $\"+13%2F4+\"$ , $\"-5%2F2+\"$ ) \r
\n" ); document.write( "\n" ); document.write( "and a directrix at $\"x+=+h+-+p+\"$
\n" ); document.write( " $\"x+=+9%2F2+-+%28-5%2F4%29++\"$
\n" ); document.write( " $\"x+=+9%2F2+%2B5%2F4+\"$
\n" ); document.write( " $\"x+=+18%2F4+%2B5%2F4+\"$
\n" ); document.write( " $\"x+=23%2F4\"$ \r
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\n" ); document.write( "\n" ); document.write( "The axis of symmetry is located at $\"y+=+k\"$ .
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\n" ); document.write( "since $\"k=-5%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y+=+-5%2F2\"$ \r
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