document.write( "Question 108862: THE LENGTH OF A RECTANGULAR GARDEN IS 6 FT LESS THAN 5 TIMES ITS WIDTH. IF THE
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document.write( "PERIMETER OF THE GARDEN IS 48 FT, FIND THE DEMINSIONS OF THE GARDEN.
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Algebra.Com's Answer #79396 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=5W-6 \n" ); document.write( "AREA=L*W \n" ); document.write( "48=(5W-6)W \n" ); document.write( "48=5W^2-6W \n" ); document.write( "5W^2-6W-48=0 \n" ); document.write( "USING THE QUADRATIC EQUATION WE GET: \n" ); document.write( " \n" ); document.write( "W=(6+-SQRT[-6^2-4*5*-48])/2*5 \n" ); document.write( "W=(6+-SQRT[36+960])/10 \n" ); document.write( "W=(6+-SQRT996)/10 \n" ); document.write( "W=(6+31.56)/10 \n" ); document.write( "W=37.56/10 \n" ); document.write( "W=3.76 FOR THE WIDTH OF THE GARDEN. \n" ); document.write( "L=5*3.76-6=12.8 FOR THE LENGTH OF THE GARDEN \n" ); document.write( "PROOF \n" ); document.write( "3.76*12.8=48 \n" ); document.write( "48=48 \n" ); document.write( " \n" ); document.write( " |