document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169274>Question 1169274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A very large jug of x litres of orange squash is 10% concentrate(the rest water). When 5 litres of concentrate is added the jug is now 12% concentrate <BR>\n" );
document.write( "A. Form an equation in terms of X( by considering the amount of concentrate we have).<BR>\n" );
document.write( "B Hence determine X\r<BR>\n" );
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document.write( "please solve this<BR>\n" );
document.write( "Regards </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793940 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39632)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x liters of 10% concentrate was mixed with 5 liters of an unknown p percent concentrate, and the result mixture was 12% concentrate.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%280.10x%2B%28p%2F100%29%2A5%29%2F%28x%2B5%29=0.12 ALIGN=MIDDLE  ALT=\"%280.10x%2B%28p%2F100%29%2A5%29%2F%28x%2B5%29=0.12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You can solve for x if you want to but you still have the unknown p % concentrate which was added to form the mixture. </SPAN>\n" );
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