document.write( "Question 1169222: Would you please verify that I have correctly done the below problem?\r
\n" ); document.write( "\n" ); document.write( "3a/a+4 - 2a^2 - 16/a^2 -16 = Below is how I did the problem:\r
\n" ); document.write( "\n" ); document.write( "3a/a + 4 + 2a^2 - 16a/(a-4)(a-4) = 3a(a-4) + (2a^2 - 16a)/ (a-4)(a+4) = 3A^2 - 12A+ 2A^2 -16/ (A-4)(A+4) = ANSWER 5A^2 - 28A / (A-40(A+4) or 5a^2 -28a/a^2 -16\r
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Algebra.Com's Answer #793921 by Edwin McCravy(20054) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "You should follow the rules of PEMDAS.  I'll try to figure out what you\r\n" );
document.write( "intended although you ignored the use of parentheses around entire\r\n" );
document.write( "numerators and entire denominators, which PEMDAS requires. \r\n" );
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document.write( "There is a discrepancy in the last term on the second fraction. On some\r\n" );
document.write( "steps you have -16 and on others you have -16a. \r\n" );
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document.write( "I think it should be -16a.\r\n" );
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document.write( "Your error in the previous step was failing to change\r\n" );
document.write( "the sign when removing parentheses preceded by a minus.\r\n" );
document.write( "But you didn't even have a parentheses there to do that\r\n" );
document.write( "to, which vitiated your answer. Maybe you just wrote a +\r\n" );
document.write( "when it should have been a -. \r\n" );
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document.write( "Edwin

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