document.write( "Question 1169252: The count in a bateria culture was 400 after 10 minutes and 1200 after 30 minutes. Assuming the count grows exponentially,\r
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document.write( "What was the initial size of the culture?
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document.write( "Find the doubling period.
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document.write( "Find the population after 80 minutes.
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document.write( "When will the population reach 14000. \n" );
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Algebra.Com's Answer #793900 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! A=Aob^x \n" ); document.write( "400=Ao^b^10 \n" ); document.write( "1200=Ao^b^30 \n" ); document.write( "3=b^20 \n" ); document.write( "b=3^(1/20)=1.056 \n" ); document.write( "not rounding \n" ); document.write( "1200=Aob^30=Ao*3^1.5 \n" ); document.write( "Ao=230.94 or 231 organisms \n" ); document.write( "- \n" ); document.write( "A=231*3^0.05^x \n" ); document.write( "Doubling is when \n" ); document.write( "2=3^0.05^x \n" ); document.write( "or ln 2=x ln 3^0.05 \n" ); document.write( "ln2=0.05x ln 3 \n" ); document.write( "20 ln2=x ln3 \n" ); document.write( "x=12.619 min or 12.6 min. \n" ); document.write( "- \n" ); document.write( "tripling time is 3=1.056^x or \n" ); document.write( "20 ln 3=x ln 3 \n" ); document.write( "x=20 minutes, which it should be. \n" ); document.write( "- \n" ); document.write( "after 80 minutes \n" ); document.write( "A=231(3^0.05)^80=231^3^4 \n" ); document.write( "=18,711 organisms \n" ); document.write( "- \n" ); document.write( "14000=231*3^0.05x \n" ); document.write( "60.606=3^(0.05)^x \n" ); document.write( "ln 60.606=x*0.05 ln 3 \n" ); document.write( "82.088=x ln3 \n" ); document.write( "x=74.72 min\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |