document.write( "Question 1169236: The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 1900 miles. What warranty should the company use if they want 96% of the tires to last longer than the warranty? \n" ); document.write( "
Algebra.Com's Answer #793882 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Want the 4th percentile z of a normal distribution, and 96% will be above that number \n" ); document.write( "z=(x-60000)/1900=-1.75 \n" ); document.write( "x-60000=-3326 \n" ); document.write( "x=56674 miles \n" ); document.write( " |