document.write( "Question 108864: AT 9:00 A.M. A TRUCK LEAVES THE TRUCK YARD AND
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document.write( "TRAVELS WEST AT A RATE OF 35 MI/HR.
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document.write( "TWO HOURS LATER, A SECOND TRUCK LEAVES ALONG THE SAME ROUTE
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document.write( "TRAVELING AT 70 MI/HR.
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document.write( "WHEN WILL THE SECOND TRUCK CATCH UP TO THE FIRST TRUCK?\r
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document.write( "THANKS
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document.write( "JMS \n" );
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Algebra.Com's Answer #79386 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! DISTANCE=RATE*TIME \n" ); document.write( "SEEING AS THE DISTANCES ARE THE SAME WE HAVE: \n" ); document.write( "35T=70(T-2) \n" ); document.write( "35T=70T-140 \n" ); document.write( "35T-70T=-140 \n" ); document.write( "-35T=-140 \n" ); document.write( "T=-140/-35 \n" ); document.write( "T=4 HOURS THEY WILL MEET. \n" ); document.write( "PROOF \n" ); document.write( "35*4=70(4-2) \n" ); document.write( "140=70*2 \n" ); document.write( "140=140 \n" ); document.write( " |