document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169140>Question 1169140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On Monday, tom drove to town at 60mph. On Tuesday, he drove to town at 40mph<BR>\n" );
document.write( "If the total drive time for both days was 15 hours, how far was it to town </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793792 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13216)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a completely different option for solving this kind of problem than the algebraic solution shown by the other tutor.<br><BR>\n" );
document.write( "The ratio of speeds is 3:2; since the distances are the same, the amounts of time are in the ratio 2:3.<br><BR>\n" );
document.write( "A ratio of 2:3 in times, with a total time of 15 hours, means 6 hours at one rate and 9 hours at the other rate.<br><BR>\n" );
document.write( "The distance to the town is 6 hours at 60 mph = 360 miles, or 9 hours at 40 mph = 360 miles.<br><BR>\n" );
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