document.write( "Question 1169114: Twice the sum of the digits of a two-digit number is 14. The original number subtracted from the number formed when the digits are reversed is 27. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #793774 by ankor@dixie-net.com(22740)\"\" \"About 
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let the two digits be a & b
\n" ); document.write( "then
\n" ); document.write( "10a + b = the original number
\n" ); document.write( ":
\n" ); document.write( "Twice the sum of the digits of a two-digit number is 14.
\n" ); document.write( "2(a+b) = 14
\n" ); document.write( "simplify divide by 2
\n" ); document.write( "a + b = 7
\n" ); document.write( " The original number subtracted from the number formed when the digits are reversed is 27.
\n" ); document.write( "(10b + a) - (10a + b) = 27
\n" ); document.write( "10b - b + a - 10a = 27
\n" ); document.write( "9b - 9a = 27
\n" ); document.write( "simplify divide by 9
\n" ); document.write( "b - a = 3
\n" ); document.write( ":
\n" ); document.write( "Use elimination with these two equations
\n" ); document.write( "a + b = 7
\n" ); document.write( "-a + b = 3
\n" ); document.write( "---------------Addition eliminates a, find b
\n" ); document.write( "0 + 2b = 10
\n" ); document.write( "b = 10/2
\n" ); document.write( "b = 5
\n" ); document.write( "then
\n" ); document.write( "a + 5 = 7
\n" ); document.write( "a = 7 - 5
\n" ); document.write( "a = 2
\n" ); document.write( ":
\n" ); document.write( " What is the original number? 25
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this in the statement:
\n" ); document.write( "\"The original number subtracted from the number formed when the digits are reversed is 27.\"
\n" ); document.write( "52 - 25 = 27 \n" ); document.write( "
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