document.write( "Question 1169125: A rectangle has perimeter 56 feet and it’s area is 180 sq feet find the dimensions of this rectangle.
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Algebra.Com's Answer #793760 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "Length =\"L\"
\n" ); document.write( "Width =\"W\"
\n" ); document.write( "perimeter=>\"P=2%28L%2BW%29\"
\n" ); document.write( "area=> \"A=LW\"\r
\n" ); document.write( "\n" ); document.write( "A rectangle has \"perimeter\" \"56\" feet we have\r
\n" ); document.write( "\n" ); document.write( "\"56ft=2%28L%2BW%29\"...solve for \"L\"
\n" ); document.write( "\"56ft%2F2=L%2BW\"
\n" ); document.write( "\"28ft-W=L\"....eq.1\r
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\n" ); document.write( "\n" ); document.write( "and it’s area is \"180\" sq feet find the dimensions of this rectangle, we have\r
\n" ); document.write( "\n" ); document.write( "\"180=LW\"..solve for \"L\"
\n" ); document.write( "\"180%2FW=L\"...........eq.2\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r
\n" ); document.write( "\n" ); document.write( "\"28ft-W=180%2FW\"....solve for \"W\"
\n" ); document.write( "\"28W-W%5E2=180\"
\n" ); document.write( "\"0=W%5E2-28W%2B180\"....factor
\n" ); document.write( "\"0=W%5E2-10W-18W%2B180\"
\n" ); document.write( "\"0=%28W%5E2-10W%29-%2818W-180%29\"
\n" ); document.write( "\"0=W%28W-10%29-18%28W-10%29%7D%7D%0D%0A%7B%7B%7B0+=+%28W+-+18%29+%28W+-+10%29\"\r
\n" ); document.write( "\n" ); document.write( "=>\"W=10ft\" or \"W=18ft\"\r
\n" ); document.write( "\n" ); document.write( "\"28ft-W=L\"....eq.1, substitute \"W=10ft\"
\n" ); document.write( "\"28ft-10ft=L\"
\n" ); document.write( "\"L=18ft\"\r
\n" ); document.write( "\n" ); document.write( "Length =\"18ft\"
\n" ); document.write( "Width =\"10ft\"\r
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