document.write( "Question 1168957: jim has one more than twice as many times than quarters. he has no other coins. if he has $3.25 in change, how many of each coin does jim have. \n" ); document.write( "
Algebra.Com's Answer #793747 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jim has one more than twice as many dimes than quarters. he has no other coins. \n" ); document.write( "d = 2q + 1 \n" ); document.write( " If he has $3.25 in change, \n" ); document.write( ".10d + .25q = 3.25 \n" ); document.write( "Replace d with (2q+1) \n" ); document.write( ".10(2q+1) + .25q = 3.25 \n" ); document.write( ".20q + .1 + .25q = 3.25 \n" ); document.write( ".45q = 3.25 - .10 \n" ); document.write( ".45q = 3.25 - .10 \n" ); document.write( "q = 3.15/.45 \n" ); document.write( "q = 7 quarters \n" ); document.write( "then \n" ); document.write( "d = 2(7) + 1 \n" ); document.write( "d = 15 dimes \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check \n" ); document.write( ".10(15) + .25(7) = \n" ); document.write( "1.50 + 1.75 = 3.25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |