document.write( "Question 1169065: Good day. May you please assist me in the following question:\r
\n" ); document.write( "\n" ); document.write( "The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary's age was 3 years more than twice Jane's age. Determine their current ages. \n" ); document.write( "

Algebra.Com's Answer #793718 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Good day. May you please assist me in the following question:\r
\n" ); document.write( "\n" ); document.write( "The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary's age was 3 years more than twice Jane's age. Determine their current ages.
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Let Mary's age be M
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document.write( "Then Jane's is: 24 - M
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document.write( "Four years ago, Mary was M - 4, and Jane's was: 24 - M - 4, or 20 - M
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document.write( "We then get:  3(M - 4) = 2(20 - M) + 3
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document.write( "3M - 12 = 40 - 2M + 3
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document.write( "3M + 2M = 55
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document.write( "5M = 55
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document.write( "Mary or 
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document.write( "Now, find Jane's age! \n" );
document.write( "

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