document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1169062>Question 1169062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system and graph the curves:<BR>\n" );
document.write( " x^2-2x-4y^2+8y-2=0 <BR>\n" );
document.write( "5x^2-10x+12y^2+24y-58=0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793717 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793717\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we multiply the 1st equation by 5 and subtract the 2nd from it, we have:<BR>\n" );
document.write( "32y^2 - 16y - 48 = 0<BR>\n" );
document.write( "Divide through by 16 and factor:<BR>\n" );
document.write( "(2y - 3)(y + 1) = 0<BR>\n" );
document.write( "y = 3/2, y = -1<BR>\n" );
document.write( "Using the 1st equation to solve for x, we get:<BR>\n" );
document.write( "x^2 - 2x - 4 - 8 - 2 = 0<BR>\n" );
document.write( "x^2 - 2x - 14 = 0 -> x= -2.8729833 and x= 4.8729833<BR>\n" );
document.write( "x^2 - 2x - 4(3/2)^2 + 8(3/2) - 2 = 0 -> x^2 - 2x + 1 = 0 -> (x-1)(x-1) = 0<BR>\n" );
document.write( "This gives x = 1, multiplicity 2<BR>\n" );
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