document.write( "Question 1169061: find a 4th degree polynomial with real coefficients satisfying the given conditions: -1,5, and 2+4i are zeros; f(1)=-272 \n" ); document.write( "
Algebra.Com's Answer #793713 by Solver92311(821)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Complex zeros always appear in conjugate pairs, so if is a zero, then must also be a zero.\r
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\n" ); document.write( "\n" ); document.write( "Your desired function then has 5 factors, one of which is a constant, thus:\r
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\n" ); document.write( "\n" ); document.write( "You can expand and collect like terms for yourself. Hint: Remember that the product of two conjugates is the difference of two squares and that .\r
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\n" ); document.write( "\n" ); document.write( "Substitute 1 for , then do the arithmetic to solve for giving you everything you need for your function.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\n" ); document.write( "\n" ); document.write( "I > Ø
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