document.write( "Question 108786: Please help me with the following question: (It is not in the book, it is on a homework assignment.)\r
\n" ); document.write( "\n" ); document.write( "The lifetime of a popular dvd player is guaranteed to be 8 years. If the lives of this dvd players are normally distributed with a mean of 8.75 and a SD of .45 years, find the percentage of the DVD players that will not meet the guarantee.
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Algebra.Com's Answer #79368 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Since you've assumed a normal distribution, you can
\n" ); document.write( "calculate your z value using the value you're intereted in, the mean and the standard deviation.
\n" ); document.write( "\"z=%28x-x%5Bm%5D%29%2F%28sigma%29\"
\n" ); document.write( "where x = 8 years (your warranty date)
\n" ); document.write( "\"z=%288-8.75%29%2F%28.45%29\"
\n" ); document.write( "\"z=-1.667\"
\n" ); document.write( "Your z score then gives you the percentage of units that failed before 8 years, that is, did not meet the guarantee.
\n" ); document.write( "At z=-1.667, the cumulative distribution function (from EXCEL) gives a value of 0.04779.
\n" ); document.write( "In other words, from 0 to 8 years, the area under the curve is 4.8% of the total area.
\n" ); document.write( "4.8% of the units failed to meet the guarantee. \r
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