document.write( "Question 108786: Please help me with the following question: (It is not in the book, it is on a homework assignment.)\r
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document.write( "The lifetime of a popular dvd player is guaranteed to be 8 years. If the lives of this dvd players are normally distributed with a mean of 8.75 and a SD of .45 years, find the percentage of the DVD players that will not meet the guarantee. \n" );
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Algebra.Com's Answer #79368 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Since you've assumed a normal distribution, you can \n" ); document.write( "calculate your z value using the value you're intereted in, the mean and the standard deviation. \n" ); document.write( " \n" ); document.write( "where x = 8 years (your warranty date) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Your z score then gives you the percentage of units that failed before 8 years, that is, did not meet the guarantee. \n" ); document.write( "At z=-1.667, the cumulative distribution function (from EXCEL) gives a value of 0.04779. \n" ); document.write( "In other words, from 0 to 8 years, the area under the curve is 4.8% of the total area. \n" ); document.write( "4.8% of the units failed to meet the guarantee. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |