document.write( "Question 1168946: Find two numbers such that one of them exceeds the other by 18 and their sum is 92.
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Algebra.Com's Answer #793602 by Theo(13342)\"\" \"About 
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let the two numbers be x and y.
\n" ); document.write( "x = y + 18
\n" ); document.write( "x + y = 92
\n" ); document.write( "replace x with y + 18 to get:
\n" ); document.write( "y + 18 + y = 92
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "2y + 18 = 92
\n" ); document.write( "subtract 18 from both sides of the equation to get:
\n" ); document.write( "2y = 74
\n" ); document.write( "solve for y to get:
\n" ); document.write( "y = 74/2 = 37
\n" ); document.write( "x = y + 18 = 55
\n" ); document.write( "x + y = 92 becomes 37 + 55 = 92 which becomes 92 = 92 which confirms the solution is correct.
\n" ); document.write( "the two numbers are 37 and 55.
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