document.write( "Question 1168951: Hi\r
\n" ); document.write( "\n" ); document.write( "There were 350 marbles in a box. 40% of them are red. There were 10% more red marbles than green marbles. The rest were white and orange. If there were twice as many white marbles as orange,how many more red than white marbles were there.\r
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Algebra.Com's Answer #793600 by math_helper(2461) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "You have enough information to figure out the number of red and green marbles:
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document.write( "From  \"350 marbles\" and \"40% of them were red\":  350*0.40 = 140 red\r
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document.write( "10% more red than green:   g + 0.10*g = 140 -->  1.10g = 140 --> g = 140/1.1 = 127.27  (this is a problem, marbles must come in whole numbers).  \r
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document.write( "In this sense, the problem can not be solved. That is, you generally count marbles in whole units, so a fractional number of green marbles makes no sense.   \r
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document.write( "Below is an EXAMPLE problem that can be solved
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document.write( "If there were 330 marbles total, you'd have 0.4*330 = 132 red,  132/1.1 = 120 green, and then you could say  (orange) + (white) = 78  ( 78 = 330-132-120) \r
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document.write( "Since we are  also told (white) = 2*(orange) we can re-write the (orange)+(white) equation as\r
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document.write( "          (orange) + 2*(orange) = 78
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document.write( "                   3*(orange) = 78  --->  orange = 26\r
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document.write( "and (white) = 2*(26) = 52\r
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document.write( "# red   = 132
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document.write( "# green = 120
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document.write( "# white =  52
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document.write( "# green =  26
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document.write( "Total   = 330    So, for 330 marbles, the problem works, but not for 350.\r
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document.write( "The given total number of marbles must be divisible by 3, 10, and 11 in order for the problem to work out (330, 660, etc.).  \r
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