document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16294>Question 16294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me with {x+12y=68<BR>\n" );
document.write( "                            {x=8y-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7936 by </B><A HREF=/tutors/aboutme.mpl?userid=pwac><B>pwac(253)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pwac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+12y=68 ----(1)<BR>\n" );
document.write( "x=8y-12  ----(2)<BR>\n" );
document.write( "These are linear equations that can be solved using substitution<BR>\n" );
document.write( "Substitute value of x in (1)with that in (2)to get:<BR>\n" );
document.write( "(8y-12)+12y=68 bracket there to highlight what has been done<BR>\n" );
document.write( "8y-12+12y=68 add 12 to both sides to remove -12 on left<BR>\n" );
document.write( "8y+12y=80 add y-terms together<BR>\n" );
document.write( "20y=80 divide both sides by 20<BR>\n" );
document.write( "y=4<BR>\n" );
document.write( "Now substitute y in(2)with 4 to get<BR>\n" );
document.write( "x=8times4-12=32-12<BR>\n" );
document.write( "x=20<BR>\n" );
document.write( "hope you understand<BR>\n" );
document.write( "Pete </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );