document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168918>Question 1168918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is 20% salt and Solution B is 45% salt. She wants to obtain 140 ounces of a mixture that is 30% salt. How many ounces of each solution should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793563 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x oz of A for 0.20x pure salt<BR>\n" );
document.write( "140-x oz of B for 63-0.45x pure salt<BR>\n" );
document.write( "the total amount of pure salt desired is 140*0.3=42 oz.\r<BR>\n" );
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document.write( "sos 0.2x+63-0.45x=42<BR>\n" );
document.write( "-0.25x=-21<BR>\n" );
document.write( "x=84 oz of 20% one answer<BR>\n" );
document.write( "140-x=60 oz  of 45% the other answer\r<BR>\n" );
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document.write( "check<BR>\n" );
document.write( "30% is 2/5 of the way from 20 to 45, so more of the 20% will be used.<BR>\n" );
document.write( "84 oz is 3/5 of the total amount, weighting the final proportions towards the lesser concentration. </SPAN>\n" );
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