document.write( "Question 1168878: The sum of the ages of two sisters, Mary and Jane, is 24 years. Four years ago three times Mary’s age was 3 years more than twice Jane’s age. Determine their current ages. \n" ); document.write( "

Algebra.Com's Answer #793531 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"system%28m%2Bj=24%2C3%28m-4%29=3%2B2%28j-4%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"3m-12=3%2B2j-8\"$
\n" ); document.write( " $\"3m=2j%2B12%2B3-8\"$
\n" ); document.write( " $\"3m-2j=7\"$
\n" ); document.write( "substitute,
\n" ); document.write( " $\"3m-2%2824-m%29=7\"$
\n" ); document.write( " $\"cross%283m-48%2Bm=7%29\"$ ------MISTAKE FOUND HERE
\n" ); document.write( " $\"cross%284m=48%2B7%29\"$
\n" ); document.write( " $\"cross%284m=55%29\"$
\n" ); document.write( " $\"cross%28m=13%263%2F4%29\"$ -------------~~maybe. Only if you could expect the year cut into twelfths or into quarters.~~\r
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