document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168855>Question 1168855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If log5√5^125=x and log2√2^64=y, the product of x and y is<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793522 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> see my worksheet below:\r<BR>\n" );
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document.write( "your solution is that the product of x and y is 2000.\r<BR>\n" );
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document.write( "the solution depends on the following concepts.\r<BR>\n" );
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document.write( "sqrt(x) = x^(1/2)\r<BR>\n" );
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document.write( "log(a^x) = x * log(a)\r<BR>\n" );
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document.write( "(x^a)^b = x^(a * b)\r<BR>\n" );
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document.write( "logb(x) = log(x)/log(b)\r<BR>\n" );
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document.write( "log(b)/log(b) = 1\r<BR>\n" );
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document.write( "to be more specific:\r<BR>\n" );
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document.write( "the following things were done to log5(sqrt(5^125))\r<BR>\n" );
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document.write( "sqrt(5^125) was converted to (5^125)^(1/2)\r<BR>\n" );
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document.write( "(5^125)^(1/2) was converted to 5^(125 * 1/2) = 5^62.5\r<BR>\n" );
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document.write( "log5(5^62.5) was converted to 62.5 * log5(5)\r<BR>\n" );
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document.write( "log5(5) was converted to log(5)/log(5)\r<BR>\n" );
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document.write( "the same things were done to log2(sqrt(2^64))\r<BR>\n" );
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document.write( "a tutorial on log base conversion can be found at <a  rel=nofollow HREF= \"http://home.windstream.net/okrebs/page57.html#:~:text=Change%20of%20base%20formula%20Log,base%20in%20the%20new%20base.&text=Solution%3A%20Change%20to%20base%2010%20and%20use%20your%20calculator.&text=Now%20use%20your%20calculator%20and%20round%20to%20hundredths.\" target = \"_blank\">http://home.windstream.net/okrebs/page57.html#:~:text=Change%20of%20base%20formula%20Log,base%20in%20the%20new%20base.&text=Solution%3A%20Change%20to%20base%2010%20and%20use%20your%20calculator.&text=Now%20use%20your%20calculator%20and%20round%20to%20hundredths.</a>\r<BR>\n" );
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document.write( "a tutorial on properties of logs can be found at <a  rel=nofollow HREF= \"http://home.windstream.net/okrebs/page56.html\" target = \"_blank\">http://home.windstream.net/okrebs/page56.html</a>\r<BR>\n" );
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document.write( "i'll be available to answer any questions you might have about this.\r<BR>\n" );
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document.write( "theo </SPAN>\n" );
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