document.write( "Question 1168760: Write the equation of a rational function that has:
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document.write( " - real zeros when x = 1 and 2
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document.write( " - a removable discontinuity when x = 3
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document.write( " - a vertical asymptote when x = 4
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document.write( " - a horizontal asymptote at y = 3 \n" );
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Algebra.Com's Answer #793422 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! needs (x-3)/(x-3) for the discontinuity. \n" ); document.write( "(x-1)(x-2) in the numerator for the roots \n" ); document.write( "(x-4) in the denominator for the asymptote \n" ); document.write( "3 in the numerator and another term with x in the denominator so that the power of the numerator and denominator are both the same to give the asymptote of 3. I used (x-4), since it did not affect the roots or the hole.\r \n" ); document.write( "\n" ); document.write( "3(x-1)(x-2)(x-3)/(x-3)(x-4)^2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |