document.write( "Question 1168783: prove that if the sum of the sequence of the roots of the equation ax^2+bx+c=0 is 1 then b^2=2ac+a^2 \n" ); document.write( "
Algebra.Com's Answer #793407 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "The roots of \"ax%5E2%2Bbx%2Bc+=+0\" are p and q such that\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"q+=+%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "which is from the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "Adding p and q has the square root terms cancel out because we have \"sqrt%28b%5E2-4ac%29\" in both p and q; the only difference is that p has the positive version and q has the negative version. Effectively we're adding \"R%2B%28-R%29+=+0\" where \"R+=+sqrt%28b%5E2-4ac%29\"\r
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\n" ); document.write( "\n" ); document.write( "So after those root terms go away, we have
\n" ); document.write( "\"p%2Bq+=+%28-b%2B%28-b%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%2Bq+=+%28-2b%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%2Bq+=+-b%2Fa\"
\n" ); document.write( "Therefore, the sum of the roots of \"ax%5E2%2Bbx%2Bc+=+0\" is \"-b%2Fa\"\r
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\n" ); document.write( "\n" ); document.write( "We're told that the roots add to 1, so we know further that,
\n" ); document.write( "\"p%2Bq+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"-b%2Fa+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"-b+=+a\"\r
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\n" ); document.write( "\n" ); document.write( "\"a+=+-b\"\r
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\n" ); document.write( "\n" ); document.write( "Let's plug that into \"b%5E2+=+2ac%2Ba%5E2\" to see what happens\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2+=+2ac%2Ba%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2+=+2%28-b%29c%2B%28-b%29%5E2\" Replace 'a' with -b\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2+=+-2bc%2Bb%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+-2bc\" Subtract b^2 from both sides\r
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\n" ); document.write( "\n" ); document.write( "From that last equation, we see that either b = 0 or c = 0.\r
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\n" ); document.write( "\n" ); document.write( "If b = 0, then a = 0, but that means \"ax%5E2%2Bbx%2Bc\" isn't quadratic. Also, a = 0 causes division by zero errors in the quadratic formula. So we must make 'a' and b nonzero. This forces c to be zero.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the equation \"b%5E2+=+2ac%2Ba%5E2\" is only true if c = 0.\r
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\n" ); document.write( "\n" ); document.write( "If we pick a nonzero c value such as c = 1, then,
\n" ); document.write( "\"b%5E2+=+2ac%2Ba%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2+=+2%28-b%29%2A1%2B%28-b%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2+=+-2%2Bb%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"0+=+-2\"
\n" ); document.write( "Which is a contradiction.
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