document.write( "Question 1168770: You have a solution containing 10% acid and a solution containing 20% acid. How much of the 20% solution must be added to 5 liters of the 10% solution to create a mixture that is 18% acid? (Note: 10% of 5L is 0.5L.) \n" ); document.write( "
Algebra.Com's Answer #793382 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Try accounting for the pure acid.\r
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\n" ); document.write( "\n" ); document.write( "\"0.1%2A5%2B0.2x=0.18%285%2Bx%29\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5%2B0.2x=0.18x%2B0.18%2A5\"\r
\n" ); document.write( "\n" ); document.write( "\"0.02x=0.18%2A5-0.5\"\r
\n" ); document.write( "\n" ); document.write( "\"0.02x=0.4\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x=20%29\"
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