document.write( "Question 1168755: Find the smallest number Θ larger than 8pi such that sinΘ = (square root2/2)
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Algebra.Com's Answer #793370 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Use a unit circle or reference table to see that
\n" ); document.write( "sin(pi/4) = sqrt(2)/2
\n" ); document.write( "note: pi/4 radians = 45 degrees\r
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\n" ); document.write( "\n" ); document.write( "From here, add on 2pi to get a coterminal angle
\n" ); document.write( "pi/4 + 2pi = pi/4 + 8pi/4 = 9pi/4\r
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\n" ); document.write( "\n" ); document.write( "Use your calculator to get
\n" ); document.write( "8pi = 25.1327412287183
\n" ); document.write( "9pi/4 = 7.06858347057703
\n" ); document.write( "So 9pi/4 is not larger than 8pi\r
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\n" ); document.write( "\n" ); document.write( "We need to add on another multiple of 2pi
\n" ); document.write( "9pi/4 + 2pi = 9pi/4 + 8pi/4 = 17pi/4
\n" ); document.write( "17pi/4 = 13.3517687777567
\n" ); document.write( "which is not bigger than 8pi = 25.1327\r
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\n" ); document.write( "\n" ); document.write( "So we need to add on yet another multiple of 2pi
\n" ); document.write( "We keep going until the result is larger than 8pi = 25.1327
\n" ); document.write( "17pi/4+2pi = 17pi/4+8pi/4 = 25pi/4
\n" ); document.write( "25pi/4 = 19.6349540849362
\n" ); document.write( "Still not big enough\r
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\n" ); document.write( "\n" ); document.write( "Add on another 2pi
\n" ); document.write( "25pi/4+2pi = 25pi/4+8pi/4 = 33pi/4
\n" ); document.write( "33pi/4 = 25.918139
\n" ); document.write( "Now this is finally bigger than 8pi = 25.1327\r
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\n" ); document.write( "Answer: theta = 33pi/4\r
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