document.write( "Question 1168751: Solve the problem.\r
\n" ); document.write( "\n" ); document.write( "The scores on a certain test are normally distributed with a mean score of 66 and a standard deviation of 3. What is the probability that a sample of 90 students will have a mean score of at least 66.3162?
\n" ); document.write( "

Algebra.Com's Answer #793368 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Given info:
\n" ); document.write( "xbar = sample mean = 66.3162
\n" ); document.write( "mu = population mean = 66
\n" ); document.write( "sigma = population standard deviation = 3
\n" ); document.write( "n = sample size = 90
\n" ); document.write( "The goal is to calculate P(xbar > 66.3162)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Calculate the standard error (SE)
\n" ); document.write( "SE = sigma/sqrt(n)
\n" ); document.write( "SE = 3/sqrt(90)
\n" ); document.write( "SE = 0.31622776601683\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use that to find the z score
\n" ); document.write( "z = (xbar - mu)/SE
\n" ); document.write( "z = (66.3162-66)/0.31622776601683
\n" ); document.write( "z = 0.9999121961453
\n" ); document.write( "z = 1.00\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The problem of finding P(xbar > 66.3162) is approximately the same as wanting to find P(Z > 1.00)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "At this point, you'll need a table or calculator.
\n" ); document.write( "If you go with a table, then you can use a table in the back of your book or you can use a free online resource like this
\n" ); document.write( "http://www.z-table.com/\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "That website shows a Z table
\n" ); document.write( "In that table, we see that P(Z < 1.00) = 0.8413
\n" ); document.write( "Look in the row that starts with 1.0 and the column that starts with 0 to find the value 0.8413
\n" ); document.write( "This represents the area under the curve to the left of the z value z = 1.00\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subtract the value from 1 to get the area under the curve to the right of the z value in question
\n" ); document.write( "1-0.8413 = 0.1587\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The final answer is 0.1587
\n" ); document.write( "This means there's roughly a 15.87% chance that xbar is larger than 66.3162
\n" ); document.write( "Use a calculator to get better accuracy.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );