document.write( "Question 1168603: Researchers had access to population data about the number of prior arrests for offenders facing prison time in Nevada. Those data included the following: mean number of prior arrests = 4, and standard deviation = 1.5.
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document.write( "A group of researchers in California wanted to examine whether or not our
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document.write( "offenders are similar to or different than Nevada’s prisoners. However, the
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document.write( "researchers were only able to get access to a sample of offenders facing prison time. The sample information included the following: mean number of prior arrests = 6, and sample size = 225.
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document.write( "The researchers in California decided to conduct a Z-test for One Sample Mean to examine potential differences in prior arrests between the two states.
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document.write( "9. The value of the observed z-statistic for the hypothesis test equals…
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document.write( "a. … 1.18.
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document.write( "b. … 2.00.
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document.write( "c. … -1.18.
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document.write( "d. … -2.00.
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document.write( "e. … 20.00.\r
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document.write( "I got E am I correct? \n" );
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Algebra.Com's Answer #793354 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x bar-mean)/sigma/sqrt(n) \n" ); document.write( "=2*15/1.5=20. You are correct. \n" ); document.write( " |