document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168722>Question 1168722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I multiplied one whole number by 18. I multiplied a second whole number by 21. I then added the two products . Of the following , which could have been the resulting sum ? .Thanks for any help <BR>\n" );
document.write( "Options are —-<BR>\n" );
document.write( "A.  1996<BR>\n" );
document.write( "B 1997<BR>\n" );
document.write( "C 1998<BR>\n" );
document.write( "D. 1999 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793334 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793334\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and y are the numbers<BR>\n" );
document.write( "18x+21y is their sum<BR>\n" );
document.write( "55*18+48*21=990+1008=1998\r<BR>\n" );
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document.write( "54*18+49*21=2001<BR>\n" );
document.write( "56*18+47*21=1008+987=1995<BR>\n" );
document.write( "57*18+46*21y=1992<BR>\n" );
document.write( "The difference in combinations is 3.<BR>\n" );
document.write( "1998 is the only even dividend in the group. When one is increased, the other decreased, there is a change of  3. \r<BR>\n" );
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document.write( "27*18+72*21=1998, so there are other combinations, but the change in difference is always 3, and 1998 is always a sum.  So are 1995 and 2001, but they aren't choices. </SPAN>\n" );
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