document.write( "Question 1168707: A random variable X has pdf f(x) = (3/4)(1-x^2) from -1 < x < 1. \r
\n" ); document.write( "\n" ); document.write( "1. Find the cdf\r
\n" ); document.write( "\n" ); document.write( "2. Find the first, second and third quartiles.\r
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\n" ); document.write( "\n" ); document.write( "I have found that the cdf = F(x) = -(x^3)/4 + 3x/4
\n" ); document.write( "by taking the integral of f(t) = (3/4)(1-t^2) from [-1,x]\r
\n" ); document.write( "\n" ); document.write( "From there I know I need to solve for F(x) = 0.25, F(x) = 0.5 and F(x) = 0.75. However when I solve for those, I keep getting values outside of the interval [-1,1].
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Algebra.Com's Answer #793308 by Boreal(15235)\"\" \"About 
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Nice job. It is quite easy to make a sign error in doing this. I made several. Your approach is just fine.\r
\n" ); document.write( "\n" ); document.write( "I set (3/4)m +3/4-(m^3/4)-(1/4)=0.25 for the 25th percentile.
\n" ); document.write( "The first term is straightforward; the second is subtracting a -3/4, so is a +3/4
\n" ); document.write( "the fourth term is (-1)^3 which is -1, then subtracted (+1) because the lower integral, then - again, 3 changes of sign.\r
\n" ); document.write( "\n" ); document.write( "Multiplying through by 4 and you get -m^3-1+3m+3=1
\n" ); document.write( "m^3-3m-1=0
\n" ); document.write( "m(q1)=-0.347
\n" ); document.write( "Md m=0
\n" ); document.write( "m(q3)=0.347\r
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