document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168702>Question 1168702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mechanic needs an antifreeze-water mixture that 60% antifreeze to fill a radiator. The mechanic has antifreeze that is a 50% concentration and antifreeze that is 100% concentration. How many liters of each concentration of antifreeze must be mixed to produce 10L of 60% antifreeze? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793285 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Target is 60% antifreeze.<BR>\n" );
document.write( "60% is closer to 50% and farther from 100%.<BR>\n" );
document.write( "MOST of the antifreeze should come from the lower concentration 50% antifreeze.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28100-60%29%2F%28100-50%29 ALIGN=MIDDLE  ALT=\"%28100-60%29%2F%28100-50%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > of the  10L is of the 50% antifreeze.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F5 ALIGN=MIDDLE  ALT=\"4%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" > of 10L is of the 50% antifreeze.\r<BR>\n" );
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document.write( "8L of 50% and 2L of 100%.\r<BR>\n" );
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document.write( "If you would do the solution with algebra and hold off on all computation until the very end, you would see that same fraction (or 1 minus it).\r<BR>\n" );
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document.write( "v, how much 100%<BR>\n" );
document.write( "10-v, how much 50%<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100v%2B50%2810-v%29=10%2A60 ALIGN=MIDDLE  ALT=\"100v%2B50%2810-v%29=10%2A60\"   DISABLED_style= \"max-width:90%; height:auto;\" >----to account for pure antifreeze itself<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100v%2B50%2A10-50v=10%2A60 ALIGN=MIDDLE  ALT=\"100v%2B50%2A10-50v=10%2A60\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100v-50v=10%2A60-10%2A50 ALIGN=MIDDLE  ALT=\"100v-50v=10%2A60-10%2A50\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28100-50%29v=10%2860-50%29 ALIGN=MIDDLE  ALT=\"%28100-50%29v=10%2860-50%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v=10%28%2860-50%29%2F%28100-50%29%29 ALIGN=MIDDLE  ALT=\"v=10%28%2860-50%29%2F%28100-50%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >------see the one-minus-the-other fraction form; depends on which antifreeze the variable is assigned.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2860-50%29%2F%28100-50%29=10%2F50=1%2F5 ALIGN=MIDDLE  ALT=\"%2860-50%29%2F%28100-50%29=10%2F50=1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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