document.write( "Question 1168683: Kerwins father is 4 years more than five times as old as him.the product og their ages in years is 204.how old is kerwin? \n" ); document.write( "
Algebra.Com's Answer #793275 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Solve informally and quickly by looking at pairs of positive integers with a product of 204 and finding a pair that satisfies the other condition.

\n" ); document.write( "1*204
\n" ); document.write( "2*102
\n" ); document.write( "3*68
\n" ); document.write( "4*51
\n" ); document.write( "6*34
\n" ); document.write( "12*17

\n" ); document.write( "34 is 4 more then 5 times 6....

\n" ); document.write( "ANSWER: Kerwin is 6 (his father is 34)

\n" ); document.write( "Suppose a formal algebraic solution was required. Then

\n" ); document.write( "x = Kerwin's age
\n" ); document.write( "5x+4 = father's age

\n" ); document.write( "\"x%285x%2B4%29+=+204\"
\n" ); document.write( "\"5x%5E2%2B4x+=+204\"
\n" ); document.write( "\"5x%5E2%2B4x-204+=+0\"

\n" ); document.write( "You could try to factor that; but for most students that would be difficult.

\n" ); document.write( "You could of course go straight to the quadratic formula to find the answer. The use of the formula is straightforward; but in this case the required calculations are not easy.

\n" ); document.write( "So at this point, I personally would go to the informal solution shown above to find the answer is x=6, and then I would continue with the formal algebraic solution.

\n" ); document.write( "\"%28x-6%29%285x%2B34%29+=+0\"
\n" ); document.write( "\"x+=+6\"

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