document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168684>Question 1168684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning. After 5 hours of burning, a candle has a height of 24 centimeters. After 18 hours of burning, its height is 16.2 centimeters. what is the height of the candle after 12 hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793269 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5, 24)<BR>\n" );
document.write( "(18, 16.2)<BR>\n" );
document.write( "slope is -7.8/13=-0.6<BR>\n" );
document.write( "after 12 hours it is -0.6*7 shorter than at 5 hours or 4.2 cm shorter or 19.8 cm  answer\r<BR>\n" );
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document.write( "the equation of the line is y-24=-0.6(x-5)<BR>\n" );
document.write( "or y=-0.6x+27<BR>\n" );
document.write( "the candle was 27 cm at 0 hours,<BR>\n" );
document.write( "-0.6*5 or -3 (24 cm) at 5 hours<BR>\n" );
document.write( "-0.6*18=-10.8 (16.2 cm) at 18 hours.'\r<BR>\n" );
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document.write( "the answer is 19.8 cm. </SPAN>\n" );
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