document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168613>Question 1168613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures:<BR>\n" );
document.write( "42.4<BR>\n" );
document.write( "66.6<BR>\n" );
document.write( "89<BR>\n" );
document.write( "62.3<BR>\n" );
document.write( "41.4<BR>\n" );
document.write( "65.8\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( "Find the 98% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793247 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean is 61.25 deg F.<BR>\n" );
document.write( "s=17.72  deg F.\r<BR>\n" );
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document.write( "half-interval is t (0.99,df=5)*s/sqrtn(n)<BR>\n" );
document.write( "=3.365*17.72/sqrt(6)<BR>\n" );
document.write( "=24.34 deg F.<BR>\n" );
document.write( "(36.91, 85.59) deg F. </SPAN>\n" );
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