document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168666>Question 1168666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> George and Dale have been assigned the same number of math problems for homework. George has finished 20 problems, and Dale has finished 4 problems. If Dale has three times as many problems remaining as George does, how many problems was George originally assigned? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793239 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of problems<BR>\n" );
document.write( "Then the remaining number of problems for George is: g = x - 20<BR>\n" );
document.write( "And for Dale is: d = x - 4<BR>\n" );
document.write( "But Dale has three times as many remaining as George, so d = 3g<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "3g = x - 4<BR>\n" );
document.write( "g = x - 20<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "3(x - 20) = x - 4<BR>\n" );
document.write( "2x = 56 -> x = 28<BR>\n" );
document.write( "Ans: 28 problems </SPAN>\n" );
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