document.write( "Question 1168539: Six prizes are to be given to six different people in a group of ten. In how many ways can a first prize, a second prize, a third prize and three fourth prizes be given? \n" ); document.write( "

Algebra.Com's Answer #793124 by math_helper(2461) $\"\"$ $\"About$

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document.write( "It is the same as the number of ways a 1st,2nd,and 3rd prize can be assigned to 6 different people (i.e. we can ignore the three fourth place prizes, as they simply fall into place after the first three prizes are given):\r
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document.write( "First choose 3 people from 6:  6C3 = 6!/((6-3)!3!) = 6*5*4/(3*2) = 20 ways to do this
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document.write( "Now assign {1st,2nd,3rd} prizes:  3P3 = 3! = 6  ways PER selection of 3 people.\r
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document.write( "Multiply 20 selections * 6 arrangements:  
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document.write( "20*6 = ways  \n" );
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