document.write( "Question 108812: 2x^2-5x=3 I am having trouble figuring this out.I am suppose to use the quadratic formula \n" ); document.write( "
Algebra.Com's Answer #79307 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2x%5E2-5x=3\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-5x-3=0\" Subtract 3 from both sides\r
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"2%2Ax%5E2-5%2Ax-3=0\" ( notice \"a=2\", \"b=-5\", and \"c=-3\")
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\n" ); document.write( " \"x+=+%28--5+%2B-+sqrt%28+%28-5%29%5E2-4%2A2%2A-3+%29%29%2F%282%2A2%29\" Plug in a=2, b=-5, and c=-3
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\n" ); document.write( " \"x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%2A2%2A-3+%29%29%2F%282%2A2%29\" Negate -5 to get 5
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\n" ); document.write( " \"x+=+%285+%2B-+sqrt%28+25-4%2A2%2A-3+%29%29%2F%282%2A2%29\" Square -5 to get 25 (note: remember when you square -5, you must square the negative as well. This is because \"%28-5%29%5E2=-5%2A-5=25\".)
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\n" ); document.write( " \"x+=+%285+%2B-+sqrt%28+25%2B24+%29%29%2F%282%2A2%29\" Multiply \"-4%2A-3%2A2\" to get \"24\"
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\n" ); document.write( " \"x+=+%285+%2B-+sqrt%28+49+%29%29%2F%282%2A2%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%285+%2B-+7%29%2F%282%2A2%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%285+%2B-+7%29%2F4\" Multiply 2 and 2 to get 4
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\n" ); document.write( " So now the expression breaks down into two parts
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\n" ); document.write( " \"x+=+%285+%2B+7%29%2F4\" or \"x+=+%285+-+7%29%2F4\"
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\n" ); document.write( " Lets look at the first part:
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\n" ); document.write( " \"x=%285+%2B+7%29%2F4\"
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\n" ); document.write( " \"x=12%2F4\" Add the terms in the numerator
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\n" ); document.write( " \"x=3\" Divide
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\n" ); document.write( " So one answer is
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\n" ); document.write( " \"x=3\"
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\n" ); document.write( " Now lets look at the second part:
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\n" ); document.write( " \"x=%285+-+7%29%2F4\"
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\n" ); document.write( " \"x=-2%2F4\" Subtract the terms in the numerator
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\n" ); document.write( " \"x=-1%2F2\" Divide
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\n" ); document.write( " So another answer is
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\n" ); document.write( " \"x=-1%2F2\"
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\n" ); document.write( " So our solutions are:
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\n" ); document.write( " \"x=3\" or \"x=-1%2F2\"
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