document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168447>Question 1168447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the length of the rectangle is 4 more than three times the width and the area is equal to 39^2. find the dimension of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #793027 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=793027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the length of the rectangle is 4 more than three times the width and the area is equal to 39^2. find the dimension of the rectangle<BR>\n" );
document.write( "solution <BR>\n" );
document.write( "Let width is x mtrs  than length =3x+4<BR>\n" );
document.write( "area= lengthx width<BR>\n" );
document.write( "39=x(3x+4)<BR>\n" );
document.write( "3x^2+4x-39=0<BR>\n" );
document.write( "3x^2+13x-9x-39=0<BR>\n" );
document.write( "(3x+13)(x-3)=0<BR>\n" );
document.write( "x=3 or x=-13/3 rejecting negative value of x therefore x=3 means width is 3 mtrs  and length will be 13 mtrs <BR>\n" );
document.write( "answer Length=13 mtrs<BR>\n" );
document.write( "    width=3 mtrs  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );