document.write( "Question 1168438: For the function f(x)=x^2+2x-15 solve the following.
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Algebra.Com's Answer #793022 by ikleyn(52797) $\"\"$ $\"About$

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document.write( "Solve the equation\r\n" );
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document.write( "    x^2 + 2x - 15 = 0\r\n" );
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document.write( "by factoring\r\n" );
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document.write( "    (x+5)*(x-3) = 0.\r\n" );
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document.write( "The roots are  x= - 5  and  x= 3.\r\n" );
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document.write( "Since the leading coefficient at x^2 is positive ( it is 1 ),  the parabola is open up.\r\n" );
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document.write( "So, it is negative between the roots and positive outside.\r\n" );
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document.write( "Thus the answer to the problem's question is this set  -5 <= x <= 3,\r\n" );
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document.write( "or, in the interval form, the set  [-5,3].\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answered, solved and explained.\r
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